How do you integrate #int(1/2)cscpitcotpitdt#?

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How do you integrate #int(1/2)cscpitcotpitdt#?

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Answer 1 · 2015-03-04T13:08:02

You can try first to change your functions as:
#csc(x)=1/sin(x)# and
#cot(x)=cos(x)/sin(x)#
so you can write:
enter image source here
Where at the end you integrate #sin^(-2)(pit)# as #x^(-2)# in a normal integral.

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How do you integrate #int(1/2)cscpitcotpitdt#?

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