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How do you integrate # e^(2x)#?

1 Answer

Konstantinos Michailidis

Jun 6, 2016

Take its derivative first hence

#(e^(2x))'=e^(2x)*2=>e^(2x)=1/2(e^(2x))'#

Hence

#int e^(2x)dx=int 1/2*(e^(2x))'dx=e^(2x)/2+c#

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