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How do you integrate #((e^(1/x^8)) / x^9 ) dx#?

1 Answer

Apr 22, 2018

# -1/8e^(1/x^8)+C#.

Explanation:

Subst. #1/x^8=x^-8=y#

#:. -8x^(-8-1)dx=-8/x^9dx=dy#.

#:. 1/x^9dx=-1/8dy#.

#:. inte^(1/x^8)/x^9dx#,

#=int-1/8e^y dy#,

#=-1/8e^y#,

#=-1/8e^(1/x^8)+C#.

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