# How do you integrate #e^(-1.5x)#?

##### 1 Answer

Jun 27, 2015

Use substitution with

#### Explanation:

Any integral of the form

# = 1/k int e^u du = 1/ke^u +C#

# = 1/ke^(kx) +C#

This answer makes sense, because the derivative of

That is: we know the integral of

Note: fraction with a decimal in the numerator or denominator looks strange to me. (I think: "Make up you mind! One or the other!")