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How do you integrate by substitution #int root3(1-2x^2)(-4x)dx#?

1 Answer

Oct 25, 2016

#= 3/4 (1- 2x^2)^(4/3) + C#

Explanation:

let #y = 1- 2x^2, dy = color(red)((- 4x) dx)#

#int root3(1-2x^2)color(red)((-4x) dx)#

#= int root3y \ color(red)(dy)#

#= int y^(1/3) \ color(red)(dy)#

#= (3 y^(4/3))/4 + C#

#= 3/4 (1- 2x^2)^(4/3) + C#

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