How do you implicitly differentiate # 3x^2-y^2=7#?

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How do you implicitly differentiate # 3x^2-y^2=7#?

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Answer 1 · 2015-11-24T03:22:54

#dy/dx=(3x)/y#

Explanation:

When we implicitly differentiate with respect to #x#, we differentiate the #x# terms like we normally would. However, when we reach a variable that's not #x# (in this case, #y#), the chain rule kicks into effect and a #dy/dx# term is spit out.

#d/dx[3x^2-y^2=7]#

#6x-2ydy/dx=0#

#-2ydy/dx=-6x#

#dy/dx=(3x)/y#

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How do you implicitly differentiate # 3x^2-y^2=7#?

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