How do you identify cot^2x(sin^2x)?
2 Answers
Mar 16, 2017
Explanation:
Mar 16, 2017
Explanation:
I am assuming you mean
color(blue)"simplify" Uing the
color(blue)"trigonometric identity"
color(red)(bar(ul(|color(white)(2/2)color(black)(cot^2x=(cos^2x)/(sin^2x))color(white)(2/2)|)))
rArrcot^2x(sin^2x)
=cos^2x/cancel(sin^2x)^1xxcancel(sin^2x)^1
=cos^2x