How do you graph #y>x-4#?

1 Answer
Aug 18, 2017

See a solution process below:

Explanation:

First, change the inequality to an equality and solve for two points on the line:

For #x = 0#

#y = 0 - 4#

#y = -4# or #(0, -4)#

For #x = 4#

#y = 4 - 4#

#y = 0# or #(4, 0)#

We can now plot the two points on the grid.

graph{(x^2+(y+4)^2-0.05)((x-4)^2+y^2-0.05)=0 [-15, 15, -7.5, 7.5]}

We can now draw a line through these two points to create the inequality boundary. The line will be a dashed line because the inequality has just a "greater than" clause and does not have a "or equal to" clause. Therefore the line is not contained in the solution set.

We will also shade to the left of the line:

graph{y-x+4>0 [-15, 15, -7.5, 7.5]}