How do you graph $y = | x - 3 |$ $y = |x-3|$ ?

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Answer 1 · 2017-04-02T15:37:06

See explanation

The two vertical lines signify something called the 'absolute value'.

This is a process that make whatever the answer inside the two lines it is considered as being positive.

So suppose $x - 3$ $x-3$ was such that $x - 3 = - 63$ $x-3=-63$

The $| x - 3 | = + 63$ $|x-3|=+63$

The consequence is that you get a general shape of a graph that is like a V.

The bottom point of the V (the pointed end) is where

$x - 3 = 0 \Rightarrow x = 3$ $x-3 =0 => x=3$

$y_{intercept} \to x = 0$ $y_("intercept")->x=0$

$y_{intercept} = | 0 - 3 | = + 3$ $y_("intercept")=|0-3| = +3$

Tony B Tony B

How do you graph y=|x−3|y = |x-3|?