How do you graph #y= |x+3|#?

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Answer 1 · 2017-06-06T16:28:14

See below

First let's set #x=0# to find the y-intercept, the point which the graph intersects the y-axis. It turns out to be:

#(0,3)#

Now, let's set #y=0#, to find the x-intercept, the point which the graph intersects the x-axis. It turns out to be:

#(-3,0)#

To find other ordered pairs, plug in a few different values of #x# and compute #y#.

#(1,4)#
#(2,5)#
#(-1,2)#
#(-4,1)#
#(-5,2)#

graph{abs(x+3) [-10, 10, -5, 5]}