How do you graph #y<x^2-5x+4#?

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How do you graph #y<x^2-5x+4#?

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Answer 1 · 2017-12-03T12:46:19

See below.

Explanation:

First graph # y=x^2-5x+4#. Use a dashed line since this is a less than and not a less than or equal to inequality and the curve will not be an included region.

With graph plotted test for values inside and outside of the parabola.

Inside parabola:

#(2,2)#

#2 < (2)^2-5(2)+4#

#2 < 4-10+4#

#2 < -2#

This is false, so included area is outside of parabola.

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How do you graph #y<x^2-5x+4#?

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