How do you graph $y \geq x^{2} + 2$ $y>=x^2+2$ ?

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Answer 1 · 2017-07-29T06:30:15

See below

$y \geq x^{2} + 2$ $y>=x^2+2$

First note that $y>=2 forall x in RR$

If we consider only the least case for $y$ we have:

$y=x^2+2$

This is the standard parabolic function $y=x^2$ transformed ("shifted") 2 units positive ("up") on the $y-$ axis.

All points greater or equal to the least case are therefore shown as the shaded area on the graph below.

graph{y>=x^2+2 [-11.28, 11.22, -1.09, 10.16]}

How do you graph y>=x^2+2y≥x2+2y>=x^2+2?