How do you graph #y=-tan(x-pi/2)#?

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Answer 1 · 2018-08-12T04:45:05

See explanation and graph.

#cot x = tan ( pi/2 - x ) - tan ( x - pi/2 ) = y#,

#x ne# ( asymptotic zero of the denominator sin x ) #kpi#,

#k = 0, +-1, +-2, +-3, ...#.

The period is the period of tan x #= pi#

Axis: y = 0

Amplitude for infinite wave length = 1/2 (space between two

consecutive asymptotes #= pi/2#

See graph, depicting all these aspects.

graph{(y sin x - cos x)(y+0x)(x+0y)(x-pi+0y)(x+pi+0y) = 0}