How do you graph $y = | x | + 5$ $y=abs(x)+5$ ?

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Answer 1 · 2016-07-26T10:36:31

$y \geq 5$ $y>=5$ . The graph is V-like right angle with vertex at (0, 5). The upward y-axis bisects the angle.

$y - 5 = | x | \geq 0 . S o, y \geq 5$ $y - 5 = |x| >=0. So, y>=5$

$y = | x | + 5$ $y=|x|+5$ is the combined equation to the pair of semi-straight lines

represented by

$y = x + 5, x \geq 0$ $y=x+5, x>=0$ and

$y = - x + 5, x \leq 0$ $y=-x+5, x<=0$

The half-lines rise from the terminal(0, 5) and include a right angle.

The angle is bisected by the upward y-axis,

graph{(y-x-5)(y+x-5)=0[-20 20 4 25]}

How do you graph y=|x|+5y=abs(x)+5?