How do you graph y=7/x+3 using asymptotes, intercepts, end behavior?

1 Answer
Narad T.
Oct 16, 2016

horizontal asymptote at y=3
Vertical asymptote at x=0

Explanation:

If you look at the equation, there is one evident asymptote which is when x=0,it's a vertical asymptote since x≠0
THe other one is when xrarr+-oo, yrarr3 So y=3 is a horizontal asymptote
To caculate the intercept with the x axis, put y=0
0=7/x +3 So 7/x=-3 and x=-7/3
See Graph
graph{3+(7/x) [-20, 20, -10, 10]}

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