How do you graph # |y|= 6- |3x|#?

1 Answer
A. S. Adikesavan
Apr 10, 2016

#|y|>=0 to |x|<=2#. Draw the four straight lines #y=+-3x+-6#. The periphery of the so formed rhombus, with vertices at #(+-2, 0) and (0, +-6)#, is the graph for the given equation.

Explanation:

#|y|>=0 to |3x|<=6 to |x|<=2#.

The given equation is the compounded equation for the quadruplet #+-y=6+-3x to y=+-3x+-6#.

These lines, in pairs, meet at #(+-2, 0) and (0, +-6)# and form a rhombus. of side #sqrt40#..

The rhombus reaches the limits #x=+-2#, from within.

Only the coordinates (x, y) of points on this rhombus are governed by the given equation. The rhombus is the graph.

Related questions
See all questions in Graphs of Absolute Value Equations
Impact of this question
2333 views around the world
You can reuse this answer
Creative Commons License