How do you graph #y=(-4x^2)/(x^2-16)# using asymptotes, intercepts, end behavior?

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Answer 1 · 2017-10-17T21:12:20

#-4x2/(x^2-16)#

Vertical asymptote :
#x = +-4#

Horizontal asymptote :
#y = -4#

Slant asymptote : No slant or oblique asymptote.

X intercept : #y=0, x = 0#
Y intercept : #x = 0, y =0#

#-4x2/(x^2-16)#

Vertical asymptote : equate denominator to 0.
#x = +-4#

Horizontal asymptote : leading coefficients division
#y = -4#

Slant asymptote : No slant or oblique asymptote as degrees are same in numerator and denominator.

X intercept : #y=0, x = 0#
Y intercept : #x = 0, y =0#

graph{-4x^2/(x^2-16) [-10, 10, -5, 5]}