How do you graph #-y>=4/3# on the coordinate plane?

1 Answer
smendyka
Oct 10, 2017

See a solution process below:

Explanation:

Multiply each side of the inequality by #color(blue)(-1)# to solve for #y# while keeping the inequality balanced. However, because we are multiplying an inequality by a negative number we must reverse the inequality operator:

#color(blue)(-1) xx -y color(red)(<=) color(blue)(-1) xx 4/3#

#y color(red)(<=) -4/3#

Or

#y >= -1 1/3#

To graph this we will draw a horizontal line at #-4/3# on the vertical axis.

The line will be a solid line because the inequality operator contains an "or equal to" clause.

We will shade below the line because the inequality operator also contains a "less than" clause:

graph{y <= -4/3 [-10, 10, -5, 5]}

Related questions
See all questions in Linear Inequalities in Two Variables
Impact of this question
1435 views around the world
You can reuse this answer
Creative Commons License