How do you graph $y = 3 x + 8$ $y = 3x + 8$ ?

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How do you graph $y = 3 x + 8$ $y = 3x + 8$ ?

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Answer 1 · 2016-04-11T14:03:39

See the explanation

Explanation:

$Determine y_{intercept}$ $color(blue)("Determine "y_("intercept"))$

At y intercept $x = 0$ $x=0$ so by substitution we have

$y_{intercept} = 3 (0) + 8$ $y_("intercept")=3(0)+8$

$y_{intercept} \to (x, y) \to (0, 8)$ $color(blue)(y_("intercept")->(x,y)-> (0,8))$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
$Determine x_{intercept}$ $color(blue)("Determine "x_("intercept")$

x intercept is at $y = 0$ $y=0$ so by substitution we have

$0 = 3 (x_{intercept}) + 8$ $0=3(x_("intercept")) +8$

$\Rightarrow x_{intercept} \to (x, y) \to (\frac{8}{3}, 0)$ $color(blue)(=>x_("intercept") ->(x,y)->(8/3 ,0)$
'~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~

Mark these two points an draw a line through them. Extend this line to edges of the axis scales.

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How do you graph $y = 3 x + 8$ $y = 3x + 8$ ?

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