How do you graph #y=(34x-2)/(16x+4)# using asymptotes, intercepts, end behavior?
1 Answer
I have managed to present the rectangular hyperbola represented by your equation.. Vertical asymptote:
Explanation:
graph{(y-17/2) (x+1/4)+9/4=0 [-40, 40, -20, 20]}
By actual division and reorganization,
This represents athe rectangular hyperbola with asymptotes #y
=17/2 and x = -1/4#.
The center is at the common point
The graph would clarify these statements.
As
As
Not easy to see in the graph, the x-intercept is 1/68 and y-intercept
is
Note that the general equation of a rectangular hyperbola is of the
form
enabling us to read the equations of the asymptotes as
