How do you graph $y = - \frac{3}{2} x + 2$ $y = -3/2x + 2$ ?

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Answer 1 · 2018-04-02T16:38:59

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (- \frac{3}{2} \cdot 0) + 2$ $y = (-3/2 * 0) + 2$

$y = 0 + 2$ $y = 0 + 2$

$y = 2$ $y = 2$ or $(0, 2)$ $(0, 2)$

Second Point: For $x = 2$ $x = 2$

$y = (- \frac{3}{2} \cdot 2) + 2$ $y = (-3/2 * 2) + 2$

$y = - 3 + 2$ $y = -3 + 2$

$y = - 1$ $y = -1$ or $(2, - 1)$ $(2, -1)$

We can next plot the two points on the coordinate plane:

graph{(x^2+(y-2)^2-0.035)((x-2)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

Now, we can draw a straight line through the two points to graph the line:

graph{(y +(3/2)x - 2)(x^2+(y-2)^2-0.035)((x-2)^2+(y+1)^2-0.035)=0 [-10, 10, -5, 5]}

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