How do you graph #y>=2x^2-2x-5#?
1 Answer
Jan 1, 2017
The graph is inserted.
Explanation:
graph{y>=2x^2-2x-5 [-6, 6, -12, 12]}
The vertex ( least-y point ) of this parabola is
For any point (x, y) on or above this parabola,
y >= 2x^2-2x-5>=-11/2#.