How do you graph #y=2-log_2 x#?

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Answer 1 · 2016-12-21T14:50:07

Graph is inserted

#x > 0#, to make logarithm real.

Changing to common logarithm,

#y=2-log x/log 2#

x-intercept ( y = 0 ) : 4

As #x to 0, y to oo#.

As # x to oo, y to -oo#.

The graph om a semi-log graph paper ( y vs X = log x ), the graph

will be a straight line

graph{(2-y)log 2-log x=0 [-5, 5, -2.5, 2.5]}