How do you graph $y=-1/3x$ ?

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Answer 1 · 2016-11-28T05:52:56

$y$ is a straight line through the origin with a slope of $-1/3$

The equation of a straight line in slope $(m)$ and intercept $(c)$ form is:
$y=mx+c$

In this example: $y=-1/3x$
$:. m=-1/3$ and $c=0$

Hence: $y$ is a straight line through the origin with a slope of $-1/3$

The graph of $y$ is shown below.

graph{-x/3 [-10, 10, -5, 5]}

How do you graph y=-1/3xy=-1/3x?