How do you graph #y<-1/2x^2-2x+4#?
1 Answer
Dec 15, 2016
See the graph and the explanation
Explanation:
The given equation represents the parabolic boundary in the graph
upon which
For the (shaded ) interior points (x, y),
graph{y<-x^2/2-x-2x+4 [-27.35, 27.34, -13.67, 13.68]}