How do you graph #x+y> -5#?

1 Answer
smendyka
Aug 22, 2017

See a solution process below:

Explanation:

First, solve for two points as an equation instead of a inequality to find the boundary line for the inequality.

For #x = 0#

#0 + y = -5#

#y = -5# or #(0, -5)#

For #y = 0#

#x + 0 = -5#

#x = -5# or #(-5, 0)#

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.

graph{(x+y+5)(x^2+(y+5)^2-0.3)((x+5)^2+y^2-0.3)=0 [-30, 30, -15, 15]}

To complete the chart of the inequality we need to make the boundary line a dashed line because there is no "or equal to" clause in the inequality. And we need to shade the right side of the line:

graph{(x+y+5)>0 [-20, 20, -10, 10]}

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