How do you graph ${(x - \frac{5}{2})}^{2} + {(y + 4)}^{2} = \frac{101}{4}$ $(x-5/2)^2 + (y+4)^2 = 101/4$ ?

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Answer 1 · 2016-10-27T04:39:58

The equation represents a circle, center $(\frac{5}{2}, - 4)$ $(5/2,-4)$ and radius $(\frac{\sqrt{101}}{2})$ $(sqrt101/2)$

The equation is
${(x - \frac{5}{2})}^{2} + {(y + 4)}^{2} = \frac{101}{4}$ $(x-5/2)^2+(y+4)^2=101/4$

This equation looks like

${(x - a)}^{2} + {(y - b)}^{2} = r^{2}$ $(x-a)^2+(y-b)^2=r^2$

Which is the equation of a circle, center (a,b) and radius r.

so we have a circle of center $(\frac{5}{2}, - 4)$ $(5/2,-4)$ and radius $\frac{\sqrt{101}}{2}$ $sqrt101/2$

How do you graph (x−52)2+(y+4)2=1014(x-5/2)^2 + (y+4)^2 = 101/4?