How do you graph $(x-5/2)^2 + (y+4)^2 = 101/4$ ?

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Answer 1 · 2016-10-27T04:39:58

The equation represents a circle, center $(5/2,-4)$ and radius $(sqrt101/2)$

The equation is
$(x-5/2)^2+(y+4)^2=101/4$

This equation looks like

$(x-a)^2+(y-b)^2=r^2$

Which is the equation of a circle, center (a,b) and radius r.

so we have a circle of center $(5/2,-4)$ and radius $sqrt101/2$

How do you graph (x-5/2)^2 + (y+4)^2 = 101/4(x-5/2)^2 + (y+4)^2 = 101/4?