How do you graph $x^2 + (y + 3)^2 = 9$ ?

1 Answer

Jan 20, 2016

This is simply the equation of th circle centered at (0, 3) and radius
$R = sqrt(9)$ to see write: $(x+-0)^2 + (y +3)^2=9$ graph{x^2+(y+3)^2=9 [-10, 10, -5, 5]}

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How do you graph $x^2 + (y + 3)^2 = 9$ ?

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How do you graph x^2 + (y + 3)^2 = 9x^2 + (y + 3)^2 = 9?

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How do you graph $x^2 + (y + 3)^2 = 9$ ?