How do you graph #x^2 + (y + 3)^2 = 9#?

1 Answer

Jan 20, 2016

This is simply the equation of th circle centered at (0, 3) and radius
#R = sqrt(9) # to see write: #(x+-0)^2 + (y +3)^2=9# graph{x^2+(y+3)^2=9 [-10, 10, -5, 5]}

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How do you graph #x^2 + (y + 3)^2 = 9#?

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