How do you graph $x^{2} + {(y + 3)}^{2} = 9$ $x^2 + (y + 3)^2 = 9$ ?

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How do you graph $x^{2} + {(y + 3)}^{2} = 9$ $x^2 + (y + 3)^2 = 9$ ?

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Answer 1 · 2016-01-20T12:16:31

This is simply the equation of th circle centered at (0, 3) and radius
$R = \sqrt{9}$ $R = sqrt(9)$ to see write: ${(x \pm 0)}^{2} + {(y + 3)}^{2} = 9$ $(x+-0)^2 + (y +3)^2=9$ graph{x^2+(y+3)^2=9 [-10, 10, -5, 5]}

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How do you graph $x^{2} + {(y + 3)}^{2} = 9$ $x^2 + (y + 3)^2 = 9$ ?

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How do you graph x^2 + (y + 3)^2 = 9x2+(y+3)2=9x^2 + (y + 3)^2 = 9?

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How do you graph $x^{2} + {(y + 3)}^{2} = 9$ $x^2 + (y + 3)^2 = 9$ ?