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How do you graph $x^{2} + y^{2} + 4 x - 4 y - 1 = 0$ $x^2+y^2+4x-4y-1=0$ ?

1 Answer

Feb 6, 2016

Complete the square

Explanation:

After completing the square, you will get

${(x + 2)}^{2} + {(y - 2)}^{2} = 3^{2}$ $(x+2)^2 + (y-2)^2 = 3^2$

This is a circle with center at $(- 2, 2)$ $(-2,2)$ and radius of 3 units.

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