# How do you graph #(x+2)^2 + (y+1)^2 =32#?

##### 1 Answer

Feb 5, 2016

Circle with the center

#### Explanation:

What you have here is a circle equation.

The standard form of a circle equation is

#(x-x_m) ^2 + (y - y_m)^2 = r^2#

which describes a circle with the center point

In your case,

#r = sqrt(32) = sqrt(16*2) = 4sqrt(2) ~~ 5.66#

Thus, you can graph a circle with the center point

graph{(x+2)^2 + (y+1)^2 = 32 [-15.54, 16.49, -8.36, 7.66]}