How do you graph the system # x + y ≥ 5# and # x – 2y > 8#?

1 Answer
Jun 3, 2015

(1) # x + y - 5 >= 0#

(2) #x - 2y - 8 > 0#

First, graph the line (1) by its y and x intercepts;
x = 0 -> y = 5
y = 0 -> x = 8
Then, use the origin as test point. Substitute x = 0, y = 0 into the inequality (1) -> -5 > 0. Not true, then the solution set area doesn't contain the origin. Color this area.
Next, graph the Line (2) by its y and x intercepts.
x = 0 -> y = -4
y = 0 -> x = 8
Use O as test point. Replace x = 0, y = 0 into (2) --> -8 > 0. Not true. Then O is outside the solution set area. Color the solution set area.
The combined solution set is the commonly shared area.