How do you graph the quadratic function and identify the vertex and axis of symmetry for $y=5/4(x-3)^2$ ?

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Answer 1 · 2018-07-02T20:58:07

Comparing the given equation: $y=5/4(x-3)^2$ or $(x-3)^2=4/5y$ with the standard form of parabola: $X^2=4AY$ we get

$X=x-3, Y=y, A=1/5$

The above parabola will have the vertex at

$X=0, Y=0$

$x-2=0, y=0$

$x=2, y=0$

$\text{Vertex}\equiv(2, 0)$

Now, the axis of symmetry of given parabola

$X=0$

$x-2=0$

$\text{axis of symmetry: }x=2$

Locate the vertex $(2, 0)$ & draw the axis of symmetry $x=2$ Draw the parabola which intersects the y-axis at $(0, 45/4)$

How do you graph the quadratic function and identify the vertex and axis of symmetry for y=5/4(x-3)^2y=5/4(x-3)^2?