How do you graph the quadratic function and identify the vertex and axis of symmetry for y=-1/3(x+1)^2+3?

1 Answer
Tony B
Apr 5, 2017

Vertex->(x,y)=(-1,3)

Axis of symmetry is at x=-1

Explanation:

If you were to expand the brackets you would get: y=-1/3x^2.....
As the coefficient of x^2 is negative the graph is of form nn

The given equation is the vertex form of a quadratic. It is called that as you may read off the vertex coordinates with only a little but of adjustment.

Given:" "y=-1/3(xcolor(red)(+1))^2color(blue)(+3)

x_("vertex")=(-1)color(red)(xx(+1) =-1
y_("vertex")=color(blue)(+3)

Vertex->(x,y)=(-1,3)

Axis of symmetry is at x=-1

Tony BTony B

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