How do you graph the line $y = - \frac{1}{2} x + 5$ $y=-1/2x+5$ ?

Question

1556 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-09-28T13:41:35

See a solution process below:

First, solve for two points which solve the equation and plot these points:

First Point: For $x = 0$ $x = 0$

$y = (- \frac{1}{2} \cdot 0) + 5$ $y = (-1/2 * 0) + 5$

$y = 0 + 5$ $y = 0 + 5$

$y = 5$ $y = 5$ or $(0, 5)$ $(0, 5)$

Second Point: For $x = 4$ $x = 4$

$y = (- \frac{1}{2} \cdot 4) + 5$ $y = (-1/2 * 4) + 5$

$y = - 2 + 5$ $y = -2 + 5$

$y = 3$ $y = 3$ or $(4, 3)$ $(4, 3)$

We can next graph the two points on the coordinate plane:

graph{(x^2+(y-5)^2-0.1)((x-4)^2+(y-3)^2-0.1)=0 [-20, 20, -10, 10]}

Now, we can draw a straight line through the two points to graph the line:

graph{(x^2+(y-5)^2-0.1)((x-4)^2+(y-3)^2-0.1)(y+0.5x-5)=0 [-20, 20, -10, 10]}

How do you graph the line y=−12x+5y=-1/2x+5?