How do you graph the line that passes through (4,-2) perpendicular to the graph #3x-2y=6#?

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Answer 1 · 2018-06-25T14:14:04

As below

#3x - 2y = 6#

#2y = 3x - 6#

#y = (3/2)x - 6#

Slope of the line #= m = 3/2#

Slope of perpendicular line #= -1/m = -2/3#

#(y - y_1) = -(1/m) (x- x_1)#

Equation of the perpendicular line passing through point #(4,-2)# is

#(y + 2) = (-2/3) (x - 4)#

#3y + 6 = -2x + 8#

#2x + 3y = 2#

Let #x= 0, y = 2/3#

Let #x = 1, y = 0#

Now we know two ordered pairs.

We can plot it on a graph sheet and join the points to form the line.