How do you graph the line that passes through (0,3) parallel to the graph #6y-10x=30#?

1 Answer
Jumbotron
Apr 28, 2018

See a solution process below..

Explanation:

Recall equation of a line;

#y = mx + c#

Where;

#m = "gradient"#

#c = "intercept"#

Now given;

#6y - 10x = 30#

#6y = 10x + 30#

#y = 10/6x + 30/6#

#y = 5/3x + 5#

Gradient #= 5/3#

Note: when two lines are parallel to each other, their gradients equals to each other and when the lines are perpendicular to eachother, the multiplication of their gradients equals #-1​#

Therefore;

Gradient of the second equation #= 5/3#

#(0,3)# let #(x,y)# be another points

#(y-3)/(x-0) = 5/3#

Cross multiplying..

#3y - 9 = 5x - 0#

#3y = 5x + 9#

#3y - 5x - 9 = 0#

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