How do you graph the inequality #y<=-x^2+5x+6#?

1 Answer
Oct 12, 2017

it's a parabola

Explanation:

you can find the x-intercepts using the quadratic equation
#-b+-sqrt((b)^2-4*a*c)/(2*a)#
then find the vertex by using #(-b)/(2*a# and #f((-b)/(2*a))#
Then to solve for the inequality, use the coordinates (0,0) for the x and y points, with your equation
#y ≤ −x^2+5x+6#
you get #0 ≤ 6#
since this is true, the area that contains the coordinate (0,0) is the correct area