How do you graph the inequality #y<-x^2+13x-36#?
1 Answer
Jan 27, 2017
Interior of this parabola, having size a = 1/4, vertex V(13/2, 25/4) and axis
Explanation:
The ( not included ) boundary
solution
giving the standard form
graph{y+x^2-13x+36<0 [-20, 20, -10, 10]}