How do you graph the inequality #y>=x+1#?

1 Answer
smendyka
Oct 5, 2017

See a solution process below:

Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For: #x = 0#

#y = 0 + 1#

#y = 1# or #(0, 1)#

For: #x = 2#

#y = 2 + 1#

#y = 3# or #(2, 3)#

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-1)^2-0.125)((x-2)^2+(y-3)^2-0.125)(1y-x-1)=0 [-20, 20, -10, 10]}

Now, we can shade the left side of the line.

graph{(1y-x-1) >= 0 [-20, 20, -10, 10]}

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