How do you graph the inequality #y<=-2/3x+4#?

1 Answer
smendyka
Mar 13, 2018

See a solution process below:

Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For: #x = 0#

#y = (-2/3 xx 0) + 4#

#y = 0 + 4#

#y = 4# or #(0, 4)#

For: #x = 3#

#y = (-2/3 xx 3) + 4#

#y = -2 + 4#

#y = 2# or #(3, 2)#

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-4)^2-0.05)((x-3)^2+(y-2)^2-0.05)(y + (2/3)x-4)=0 [-10, 10, -5, 5]}

Now, we can shade the left side of the line.

graph{(y + (2/3)x-4) <= 0 [-10, 10, -5, 5]}

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