How do you graph the inequality #x+y>1#?

1 Answer
smendyka
Mar 14, 2018

See a solution process below:

Explanation:

First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.

For: #x = 0#

#0 + y = 1#

#y = 1# or #(0, 1)#

For: #y = 0#

#x + 0 = 1#

#x = 1# or #(1, 0)#

We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.

graph{(x^2+(y-1)^2-0.05)((x-1)^2+y^2-0.05)(x+y-1)=0 [-10, 10, -5, 5]}

Now, we can shade the rightside of the line.

The boundary line will be changed to a dashed line because the inequality operator does not contain an "or equal to" clause.

graph{(x+y-1) > 0 [-10, 10, -5, 5]}

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