How do you graph the inequality #x^2 – 12x + 32 <12#?

1 Answer
Tony B
Mar 29, 2016

See the explanation

Explanation:

Given#" "x^2-12x+32<12#

Write as:

#" "x^2-12x+32-12 < y#

#y>x^2-12x+20#

Now solve as a normal quadratic. Bulk a table of values and plot the curve. Remember that #y# can not take on the actual curve value. It is stated as #y >" and not as "y>=#. The last one is the context in which #y# could take on the value of the curve.

Tony B

Or if you multiply everything by (-1) you get

#-y<-x^2+12x-20#

Notice that this action turned > into < and that also #y# became negative.#color(brown)(" However, both curves turn out to be the same.")#

Tony B

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