How do you graph the inequality #8x+y<=6#?
1 Answer
Oct 8, 2017
See a solution process below:
Explanation:
First, solve for two points as an equation instead of an inequality to find the boundary line for the inequality.
For:
For:
We can now graph the two points on the coordinate plane and draw a line through the points to mark the boundary of the inequality.
The boundary line will be solid because the inequality operator contains an "or equal to" clause.
graph{(x^2+(y-6)^2-0.25)((x-2)^2+(y+10)^2-0.25)(8x+y-6)=0 [-30, 30, -15, 15]}
Now, we can shade the left side of the line.
graph{(8x+y-6) <= 0 [-30, 30, -15, 15]}
