How do you graph #sin (x + (3pi)/2)#?

Question

3303 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2017-12-12T18:11:59

As shown below: graph{sin(x+ (3pi)/2 ) [-4.87, 5.61, -2.62, 2.62]}

This question concerns transformations of functions:

We recall: #f(x+alpha) # represents a transformation of #(-alpha,0)#
or #alpha# units to the left:

So #sin(x+ (3pi)/2 ) # is just #sinx# shited #(3pi)/2 # to the left:

#sinx# :

graph{sinx [-4.076, 4.075, -2.038, 2.038]}

#sin(x + (3pi)/2 ) # :

graph{sin(x+ (3pi)/2 ) [-4.87, 5.61, -2.62, 2.62]}