How do you graph #log_2 (x)#?

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How do you graph #log_2 (x)#?

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Answer 1 · 2016-04-26T02:20:52

#y = log_2x#. Use the inverse relation #x = 2^y#. Sample data {(x, y)}, for making the graph:
(1/8, -3) (1/4, -2) (1/2, -1) (1, 0) (2, 1) (4, 2) (8, 3).

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How do you graph #log_2 (x)#?

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