How do you graph $g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x) = (x-4)^2/(x+2)$ ?

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How do you graph $g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x) = (x-4)^2/(x+2)$ ?

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Answer 1 · 2018-02-03T15:25:12

x=4 is a zero of the function
$g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x)=(x-4)^2/(x+2)$
while, x = -2 is an asymptote of the function

Explanation:

The given function is
$g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x)=(x-4)^2/(x+2)$
By inspection, the denominator
$x + 2 = 0, w h e n x = - 2$ $x+2=0, when x = -2$
Thus,
$x = - 2$ $x = -2$
forms an asymptote where the function reaches a value infinity
The numerator is a function ${(x - 4)}^{2}$ $(x-4)^2$
which has zero which is unique and at $x = 4$ $x = 4$
These concepts described form a strong understanding of how to draw the graph of the function
$g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x)=(x-4)^2/(x+2)$

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How do you graph $g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x) = (x-4)^2/(x+2)$ ?

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Explanation:

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How do you graph $g (x) = \frac{{(x - 4)}^{2}}{x + 2}$ $g(x) = (x-4)^2/(x+2)$ ?