How do you graph #g(x) = (x-4)^2/(x+2)#?

1 Answer
Shiva Prakash M V
Feb 3, 2018

x=4 is a zero of the function
#g(x)=(x-4)^2/(x+2)#
while, x = -2 is an asymptote of the function

Explanation:

The given function is
#g(x)=(x-4)^2/(x+2)#
By inspection, the denominator
#x+2=0, when x = -2#
Thus,
# x = -2#
forms an asymptote where the function reaches a value infinity
The numerator is a function #(x-4)^2#
which has zero which is unique and at #x = 4#
These concepts described form a strong understanding of how to draw the graph of the function
#g(x)=(x-4)^2/(x+2)#

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