How do you graph #f(x)=-(x+4)/2# using holes, vertical and horizontal asymptotes, x and y intercepts?

1 Answer
Spandex G.
Jul 9, 2017

This function is not a rational function but rather can be broken down.

Explanation:

(-x+4)/2 can be rewritten as - #1/2x+2#. This is a simple linear function without asymptotes or holes. An asymptote occurs when you have a (x) on the bottom of your function. The value that causes (x) to become zero and make the function undefined is your asymptote. Holes occur when terms containing (x) can be cancelled of from the numerator and the denominator. This causes that gap in your function when graphed. However neither of these 2 are in your example.

Related questions
See all questions in Graphs of Rational Functions
Impact of this question
1371 views around the world
You can reuse this answer
Creative Commons License