How do you graph #f(x) = 4 sin(x - pi/2 ) + 1#?

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Answer 1 · 2018-07-28T12:43:14

As below.

Standard form of sine function is #f(x) = A sin (Bx - C) + D#

Given #f(x) = 4 sin (x - pi/2) + 1#

#A = 4, B = 1, C = pi/2, D = 1#

#Amplitude = |A| = 4,

Period # = (2pi) / |B| = (2pi)/1 = 2pi#

Phase Shift #= -C / B = -(pi/2) / (1) = -pi/2, color(brown)(pi/2# to the LEFT.

Vertical Shift #D = 1#

graph{4 sin(x - pi/2) + 1 [-10, 10, -5, 5]}