How do you graph f(x)=2x−1x+3 using holes, vertical and horizontal asymptotes, x and y intercepts?

1 Answer
Lucy
Jul 11, 2018

Below

Explanation:

f(x)=2x−1x+3
f(x)=2(x+3)−7x+3
f(x)=2−7x+3

Therefore, the horizontal asymptote is y=2 and the vertical asymptote is x=−3 What asymptotes mean is that the end points of your lines are APPROACHING y=2 and x=−3

Now, to find the intercepts
When y=0, x=12
When x=0, y=−13

After plotting the intercepts and the asymptotes, you should get something like this
graph{(2x-1)/(x+3) [-10, 10, -5, 5]}

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