How do you graph # f(x) = 2abs x+1 #?

1 Answer
George C.
Jun 4, 2015

When #x >= 0# we have #f(x) = 2abs(x) + 1 = 2x+1#, which is a straight line of slope #2#, starting from #(0, 1)#

When #x <= 0# we have #f(x) = 2abs(x)+1 = -2x+1#, which is a straight line of slope #-2#, ending at #(0, 1)#

So #f(x)# is basically a 'V' shape of slope #+-2# with vertex at #(0, 1)#

graph{abs(2x)+1 [-10.04, 9.96, -2.24, 7.76]}

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